Introduction and Investigate a New Generalized Double Zeta Function
by Vijaya Bai*, Dr. Ashwini Kumar,
- Published in Journal of Advances and Scholarly Researches in Allied Education, E-ISSN: 2230-7540
Volume 14, Issue No. 1, Oct 2017, Pages 321 - 324 (4)
Published by: Ignited Minds Journals
ABSTRACT
Within this section, we extant and learn a original generalized double zeta function
KEYWORD
Introduction, Investigate, New, Generalized Double Zeta Function
INTRODUCTION
The Generalized Riemann Zeta Function
The generalized Riemann zeta function is indicated by y,z,a beside with is distinct by [17, p.27, § 1.11, Eq.(1)], watch also [49, p.159, Eq.(5)]:
n zn0
yy,z,a na
(6.1.1)
aC/0,1,2,...,zCwheny1and Re(z)>1 when y1 The over task is the generalization of the excellent generalized (Hurwitz) zeta function (, a) and Riemann Zeta function () [17, p.24, § 1.10, Eq.(1) ; p.32, § 1.12,q.(1)]. Lin and Srivastava [81] identified and explore the successive generalization of the Hurwitz-Lerch zeta function y,z,a well-known as:
n,n,zn0n
yy,z,a na
(6.1.2)
where C;a,C0,1,2,...;,R;when y,zC: for yC; , zCfor y1; , Rez1 for z1. If we take 1 in the over equation (6.1.2), we obtain
n1,1n,1zn0
yy,z,ay,z,anan!
(6.1.3)
now y,z,astands for generalized Hurwitz-Lerch zeta function distinct by Goyal and Laddha [35]. Jain [53, p.147, Eq.(6.2.5)] given and measured a innovative generalized Hurwitz-Lerch zeta function which is described and verbal to in the following way:
nnn,,sn0n
zz,s,an!na
(6.1.4)
(,a0,1,2,...sC, when z1 and Res0when z1).
series:
z2m0n0z;a,anm
;Rez2(6.1.5) Bin Saad [7] newly give a generalization of double zeta function as
m mm0
xx,y;z,ay,z,amm!
(6.1.6)
where
x1,y1;C/0,1,2,...,C/0;aC/nm,
n,mN0.
GENERALIZED DOUBLE ZETA FUNCTION
Roused by the different generalizations of Riemann zeta function, we introduce here another generalization of the double zeta function characterized by
m,,mm m0m
xx;y,z,ay,z,amm!
(6.1.7)
or
nm,,mmzm0n0m
yxx;y,z,am!anm
(6.1.8)
,C,C/0,1,2,...forx1andRez0forx1
C/0;aC/nm,zC for y1 and Re(z)>1 for y1.
RELATIONSHIP OF ,,x;y,z,aWITH KNOWN
FUNCTIONS:
(i) If we find y=0 and1 in (6.1.8), it yields the universal Hurwitz-Lerch zeta function ,,x,z,a. ,,,,1x;0,z,ax,z,a (6.2.1) (ii) additional on taking 1in (6.2.1), we find ,1,11x;0,z,ax,z,a (6.2.2) (iii) If we find x=0 in (6.1.8), we demonstrate at a generalization of the Hurwitz-Lerch zeta function y,z,adistinct by (6.1.1) as follows: (iv) For y=1, equation (6.2.3) yields the relation among generalized double zeta function and Hurwitz (or generalized) zeta function as: ,,0;1,z,az,a (6.2.4) which, further for a =1, gives the affinity with the recognized Riemann zeta function z. (v) It is not strong to observe from the definition (6.1.8), in link with (6.1.5) and (6.1.6) that ,1,1x;y,z,ax;y,z,a (6.2.5) and 1,1,121;1,z,az;a, (6.2.6)
(I) RECURRENCE RELATIONS FOR THE FUNCTION ,,:
In this part, we shall get eight reappearance relations for the generalized double zeta function,,. If ,C,C/0,1,2,... for x1 then (i) ,,,,1,1,1x;y,z,ax;y,z,ax;y,z,a (6.3.1) (ii),,1,,,1,x;y,z,ax;y,z,ax;y,z,a (6.3.2) (iii) ,,1,,1x;y,z,ax;y,z,a- ,,11x;y,z,a (6.3.3) (iv) ,,,,1,,x;y,z,axx;y,z,ax;y,z,a 1,,1,,1xx;y,z,axx;y,z,a (6.3.4) (v) ,,1,,,,x;y,z,ax;y,z,axx;y,z,a = 1,,1xx;y,z,a(6.3.5) (vi) ,,,,2x;y,z,axx;y,z,a
(6.3.6)
(vii) ,,,,xx;y,z,axx;y,z,a =1,,1,,,1,xx;y,z,ax;y,z,a1xx;y,z,a 1,,1xx;y,z,a (6.3.7) (viii) 1,,,,,,dx;y,z,ax;y,z,axx;y,z,adx (6.3.8) Proof of (i): To prove (6.3.1), we first express the generalized double zeta function in its left hand side in series frame with the assistance of (6.1.7), we obtain
mmm m0m
xy,z,amm!
mmm m0m
xy,z,am1m!
mmm m0m
mxy,z,amm!m
(6.3.9)
mmm m0m
1xy,z,am1m!
,1,1x;y,z,a which is the right hand side of (6.3.1) and this completes the proof. The proof of (6.3.2) and (6.3.3) can be simply developed in a parallel way. Proof of (iv): To set up (6.3.4),we initiate with its left hand side and state the function ,, in series form with the help of (6.1.7) in the first and third term, we obtain =
mmmm0m
xy,z,amm!
+ ,,xx;y,z,a
mmm m0m
1xy,z,amm!
1,,xx;y,z,a = m0mm! + ,,xx;y,z,a
mmm m0m
xmy,z,amm!
1,,xx;y,z,a =
mmmm1m
xy,z,amm1!
+
,,xx;y,z,a 1,,xx;y,z,a At last supplanting m by m+1 in the primary summation, we land at the correct hand side of (6.3.4) after a little improvement.
REFERENCES
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